# Challenge

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## Divisible by 3

Define a function named `div_3`

that returns `True`

if its single integer parameter is
divisible by 3 and `False`

otherwise.

For example, `div_3(6)`

is `True`

because `6/3`

does not leave any remainder.
However `div_3(5)`

is `False`

because `5/3`

leaves `2`

as a remainder.

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